document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64022>Question 64022</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395771161/algebrahomeworkh>Algebra Structure and Method Book1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is 10m longer than it is wide.If its length and width are both decreased by 2 m,its area is decreased by 48 m squared.Find its original dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44806 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L*W=AREA<BR>\n" );
document.write( "(W+10)W=(W-10-2)(W-2)+48<BR>\n" );
document.write( "W^2+10W=(W-12)(W-2)+48<BR>\n" );
document.write( "W^2+10W=W^2-12W-2W+24+48<BR>\n" );
document.write( "10W+14W=72<BR>\n" );
document.write( "24W=72<BR>\n" );
document.write( "W=72/24<BR>\n" );
document.write( "W=3 SOLUTION<BR>\n" );
document.write( "L=3+10=13 SOLUTION<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "13*3=(3-12)(3-2)+48<BR>\n" );
document.write( "39=-9*1+48<BR>\n" );
document.write( "39=-9+48<BR>\n" );
document.write( "39=39<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );