document.write( "Question 732705: If cot theta = -3/4 and cos theta > 0, find sin theta.\r
\n" ); document.write( "\n" ); document.write( "1) -4/5
\n" ); document.write( "2) -3/5
\n" ); document.write( "3) 3/5
\n" ); document.write( "4) 4/5\r
\n" ); document.write( "\n" ); document.write( "Please show work so I can understand how to do this thank you
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Algebra.Com's Answer #448010 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"cot%28theta%29=cos%28theta%29%2Fsin%28theta%29\"
\n" ); document.write( "Let's find \"x=sin%28theta%29\"
\n" ); document.write( "If \"x=sin%28theta%29\" then \"cos%28theta%29=sqrt%281-x%5E2%29\" and
\n" ); document.write( "\"cot%28theta%29=sqrt%281-x%5E2%29%2Fx\" so \"sqrt%281-x%5E2%29%2Fx=-3%2F4\"
\n" ); document.write( "and squaring both sides we get \"%281-x%5E2%29%2Fx=%28-3%2F4%29%5E2\" --> \"%281-x%5E2%29%2Fx=9%2F16\"
\n" ); document.write( "\"%281-x%5E2%29%2Fx%5E2=9%2F16\" --> \"1%2Fx%5E2-1=9%2F16\" --> \"1%2Fx%5E2=1%2B9%2F16\" --> \"1%2Fx%5E2=25%2F16\" --> \"x%5E2=16%2F25\" --> \"x=-4%2F5\" or \"x=4%2F5\"
\n" ); document.write( "But since \"cos%28theta%29%3E0\" and \"cot%28theta%29=cos%28theta%29%2Fsin%28theta%29=-3%2F4%3C0\"
\n" ); document.write( "\"sin%28theta%29%3C0\" so \"x=highlight%28sin%28theta%29=-4%2F5%29\"
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