document.write( "Question 64152: Members of the Ski Club contributed equally to obtain $1800 for a holiday trip. When 6 members found that they could not go, their contributions were refunded and each remaining member then had to pay $10 more to raise the $1800. How many went on the trip? \n" ); document.write( "
Algebra.Com's Answer #44801 by checkley71(8403)\"\" \"About 
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1800=m*c m=members & c=contribution
\n" ); document.write( "m=1800/c also
\n" ); document.write( "1800=(m-6)(c+10)
\n" ); document.write( "1800=(1800/c-6)(c+10)
\n" ); document.write( "1800=1800+18000/c-6c-60
\n" ); document.write( "-18000/c+60=-6c now multiply every term by c to eliminate the c in the denominator
\n" ); document.write( "-18000+60c=-6c^2
\n" ); document.write( "6c^2+60c-18000=0 divide all terms by 6
\n" ); document.write( "c^2+10c-3000=0
\n" ); document.write( "(c-50)(c+60)=0
\n" ); document.write( "c=50 & c=-60 the original cost is $50 then there were 1800/50=36 contributors
\n" ); document.write( "when 6 backed out there were 30 & they paid $60 each
\n" ); document.write( "proof
\n" ); document.write( "1800=30*60
\n" ); document.write( "1800=1800
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