document.write( "Question 64152: Members of the Ski Club contributed equally to obtain $1800 for a holiday trip. When 6 members found that they could not go, their contributions were refunded and each remaining member then had to pay $10 more to raise the $1800. How many went on the trip? \n" ); document.write( "
Algebra.Com's Answer #44801 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 1800=m*c m=members & c=contribution \n" ); document.write( "m=1800/c also \n" ); document.write( "1800=(m-6)(c+10) \n" ); document.write( "1800=(1800/c-6)(c+10) \n" ); document.write( "1800=1800+18000/c-6c-60 \n" ); document.write( "-18000/c+60=-6c now multiply every term by c to eliminate the c in the denominator \n" ); document.write( "-18000+60c=-6c^2 \n" ); document.write( "6c^2+60c-18000=0 divide all terms by 6 \n" ); document.write( "c^2+10c-3000=0 \n" ); document.write( "(c-50)(c+60)=0 \n" ); document.write( "c=50 & c=-60 the original cost is $50 then there were 1800/50=36 contributors \n" ); document.write( "when 6 backed out there were 30 & they paid $60 each \n" ); document.write( "proof \n" ); document.write( "1800=30*60 \n" ); document.write( "1800=1800 \n" ); document.write( " \n" ); document.write( " |