document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8101>Question 8101</A>: <I><SPAN STYLE=\"word-break: break-all;\"> bill invested $30,000 in two seperate accounts paying 3% and 4.1% annual simple interest. if bill earned a total of of $1091.73 from the two investments, how much was invested in each account.\r<BR>\n" );
document.write( "\n" );
document.write( "I have no clue how to come up with the equation of this problem. The instructions say to find the equation for this investments problem andsolve it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4480 by </B><A HREF=/tutors/aboutme.mpl?userid=srinivas123><B>srinivas123(23)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=srinivas123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4480\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one amount be x then the second amount is 30000-x <BR>\n" );
document.write( "Interest on first ammount i=ptr/100 <BR>\n" );
document.write( "(x*1*3 )/ 100. ----------------------equation (1) <BR>\n" );
document.write( "Interest on second amount i=((30000-x)*1*4.1 )/ 100-------------equaion (2) <BR>\n" );
document.write( "so total interest is equation (1) + (2) <BR>\n" );
document.write( "3x/100 + 4.1(30000-x)/100 = 1091.73 <BR>\n" );
document.write( "after cross multiplication we get<BR>\n" );
document.write( "3x+4.1(30000-x)= 109173<BR>\n" );
document.write( "3x+123000-4.1x = 109173 <BR>\n" );
document.write( "-1.1x = -13827 <BR>\n" );
document.write( "------> x=12570 <BR>\n" );
document.write( "hence first amount is $12570 and second amount is $17430.00. <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );