document.write( "Question 1421: The width of a rectangle is 45% of the length. If the perimeter of the rectangle is 58cm, find its width. \n" ); document.write( "
Algebra.Com's Answer #448 by usyim88hk(158)\"\" \"About 
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let x be the length of the rectangle
\n" ); document.write( "45%x = width of rectangle
\n" ); document.write( "x+x+45%x+45%x = 58 = perimeter of the rectangle
\n" ); document.write( "2.9x = 58
\n" ); document.write( "x = 20
\n" ); document.write( "So the length of the rectangle is 20 cm and the width of the rectangle is 45% of 20 which is 9
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