document.write( "Question 732670: Solve the equation by completing the square t^2+t-28=0 \n" ); document.write( "
Algebra.Com's Answer #447976 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "here is your solution, you just put \"t\" instead of \"x\" and \"0\" instead of \"y\":\r
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Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form

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\n" ); document.write( " \"y=1+x%5E2%2B1+x-28\" Start with the given equation
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\n" ); document.write( " \"y%2B28=1+x%5E2%2B1+x\" Add \"28\" to both sides
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\n" ); document.write( " \"y%2B28=1%28x%5E2%2B1x%29\" Factor out the leading coefficient \"1\"
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\n" ); document.write( " Take half of the x coefficient \"1\" to get \"1%2F2\" (ie \"%281%2F2%29%281%29=1%2F2\").
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\n" ); document.write( " Now square \"1%2F2\" to get \"1%2F4\" (ie \"%281%2F2%29%5E2=%281%2F2%29%281%2F2%29=1%2F4\")
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\n" ); document.write( " \"y%2B28=1%28x%5E2%2B1x%2B1%2F4-1%2F4%29\" Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of \"1%2F4\" does not change the equation
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\n" ); document.write( " \"y%2B28=1%28%28x%2B1%2F2%29%5E2-1%2F4%29\" Now factor \"x%5E2%2B1x%2B1%2F4\" to get \"%28x%2B1%2F2%29%5E2\"
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\n" ); document.write( " \"y%2B28=1%28x%2B1%2F2%29%5E2-1%281%2F4%29\" Distribute
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\n" ); document.write( " \"y%2B28=1%28x%2B1%2F2%29%5E2-1%2F4\" Multiply
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\n" ); document.write( " \"y=1%28x%2B1%2F2%29%5E2-1%2F4-28\" Now add \"%2B28\" to both sides to isolate y
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\n" ); document.write( " \"y=1%28x%2B1%2F2%29%5E2-113%2F4\" Combine like terms
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\n" ); document.write( " Now the quadratic is in vertex form \"y=a%28x-h%29%5E2%2Bk\" where \"a=1\", \"h=-1%2F2\", and \"k=-113%2F4\". Remember (h,k) is the vertex and \"a\" is the stretch/compression factor.
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\n" ); document.write( " Check:
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\n" ); document.write( " Notice if we graph the original equation \"y=1x%5E2%2B1x-28\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C1x%5E2%2B1x-28%29\" Graph of \"y=1x%5E2%2B1x-28\". Notice how the vertex is (\"-1%2F2\",\"-113%2F4\").
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\n" ); document.write( " Notice if we graph the final equation \"y=1%28x%2B1%2F2%29%5E2-113%2F4\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C1%28x%2B1%2F2%29%5E2-113%2F4%29\" Graph of \"y=1%28x%2B1%2F2%29%5E2-113%2F4\". Notice how the vertex is also (\"-1%2F2\",\"-113%2F4\").
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\n" ); document.write( " So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.
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