document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64142>Question 64142</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> pleas ehelp to solve\r<BR>\n" );
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document.write( "-2x - 4^0 - x / 3 + x + 3^0 / 5 = 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44794 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2x - 4^0 - x / 3 + x + 3^0 / 5 = 3 [any number raised to zero equals 1]<BR>\n" );
document.write( "-2x - (1) - x / 3 + x + 1 / 5 = 3<BR>\n" );
document.write( "15(-2x - (1) - x / 3 + x + 1 / 5 = 3) [multiply through by a 15 in order to get rid of the fractions]<BR>\n" );
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document.write( "-30x-15-5x+15x+3=45 [multiply the entire equation through by 15<BR>\n" );
document.write( "-20x-12=45    [combine like-terms]<BR>\n" );
document.write( "-20x=45+12 [solve for x]<BR>\n" );
document.write( "-20x=57<BR>\n" );
document.write( "x=-57/20 </SPAN>\n" );
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