document.write( "Question 732606: This is a question I had trouble with:
\n" ); document.write( " From a group of 5 boys and 4 girls, a committee of 4 must be selected. The committee must have at least one boy and at least one girl. How many ways can this be done? \n" ); document.write( "

Algebra.Com's Answer #447926 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "There are 5 ways to choose the required 1 boy. Then, for each of those 5 ways, there are 4 ways to choose the required 1 girl. Then for each of those 20 ways, there remain 7 people, so 7 ways to choose the third committee member, and finally 6 ways to choose the fourth committee member. Altogether, 5 times 4 times 7 times 6. You can do your own arithmetic.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John
\n" ); document.write( "

\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
\n" ); document.write( "

$\"The$

\n" ); document.write( " \n" ); document.write( "

\n" );