document.write( "Question 732550: Hi\r
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document.write( "ax-y=5
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document.write( "x+y=4\r
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document.write( "Answer is a>5/4. Need to find \"a\" values that make x and y positive. Explanations are greatly appreciated!!\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #447920 by josgarithmetic(39621)![]() ![]() ![]() You can put this solution on YOUR website! Solve the system for x and y and get \n" ); document.write( "x=9/(a+1) and y=(4a-5)/(a+1).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking the result of y, Either numerator and denominator both positive OR numerator and denominator both negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I did not yet finish complete analysis but:\r \n" ); document.write( "\n" ); document.write( "4a-5>0 AND a+1>0 means, through use of number line graphing, a>5/4 \n" ); document.write( "OR \n" ); document.write( "4a-5<0 AND a+1<0 means, again through care with a number line, a<-1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As said, not yet finished.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking how \"a\" works for x, we must have the denominator, a+1 POSITIVE so we say, \n" ); document.write( " \n" ); document.write( "How does this fit with what was found for y? The part before the \"OR\" is what is consistant (tentatively) for \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now as long as we must have the conditions, \n" ); document.write( "So the answer is |