document.write( "Question 732550: Hi\r
\n" ); document.write( "\n" ); document.write( "ax-y=5
\n" ); document.write( "x+y=4\r
\n" ); document.write( "\n" ); document.write( "Answer is a>5/4. Need to find \"a\" values that make x and y positive. Explanations are greatly appreciated!!\r
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Algebra.Com's Answer #447920 by josgarithmetic(39621)\"\" \"About 
You can put this solution on YOUR website!
Solve the system for x and y and get
\n" ); document.write( "x=9/(a+1) and y=(4a-5)/(a+1).\r
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\n" ); document.write( "\n" ); document.write( "Note that \"a%3C%3E-1\".\r
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\n" ); document.write( "\n" ); document.write( "Checking the result of y, Either numerator and denominator both positive OR numerator and denominator both negative.\r
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\n" ); document.write( "\n" ); document.write( "I did not yet finish complete analysis but:\r
\n" ); document.write( "\n" ); document.write( "4a-5>0 AND a+1>0 means, through use of number line graphing, a>5/4
\n" ); document.write( "OR
\n" ); document.write( "4a-5<0 AND a+1<0 means, again through care with a number line, a<-1.\r
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\n" ); document.write( "\n" ); document.write( "As said, not yet finished.\r
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\n" ); document.write( "\n" ); document.write( "Checking how \"a\" works for x, we must have the denominator, a+1 POSITIVE so we say, \"a%2B1%3E0\",
\n" ); document.write( "\"a%3E-1\".
\n" ); document.write( "How does this fit with what was found for y? The part before the \"OR\" is what is consistant (tentatively) for \"a%3E-1\". The part after the \"OR\" is no good in this problem description. Why? because MUST \"a%3E-1\".\r
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\n" ); document.write( "\n" ); document.write( "Now as long as we must have the conditions,\"+a%3E5%2F4\" and/or \"a%3E-1\", the common set in these two is \"a%3E5%2F4\";
\n" ); document.write( "So the answer is \"highlight%28a%3E5%2F4%29\".
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