document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=732580>Question 732580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I ned help understanding how to do these two problems, I have looked through my book and I don't understand.\r<BR>\n" );
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document.write( "Given: f(x)=1-3x^2 and g(x)=sqrt 4-x<BR>\n" );
document.write( "A) F dot G (2)  B) G dot F (-2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #447916 by </B><A HREF=/tutors/aboutme.mpl?userid=lokesh+mishra><B>lokesh mishra(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lokesh+mishra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=447916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F.G MEANS THE VALUE OF FUNCTION F AT G , PUT G IN PLACE OF X IN F, SO ANS IS FOLLOW F.G = 1-3{G(X)}^2 = 1-3{SQRT(4-X)}^2 = 1-3(4-X) = 1-12+3X= 3X-11  , SIMILARLY G.F , </SPAN>\n" );
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