document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=732579>Question 732579</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the logarithmic equation.reject any value of x that is not in the domain of the original logarithmic expression. log (x + 16) = log x + log 16 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #447915 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=447915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Righthand side is log(x*16), so the equation shown can be same as log(x+16)=log(16*x).  Meaning is x+16=16x.  <BR>\n" );
document.write( "x-16x=-16<BR>\n" );
document.write( "-15x=-16<BR>\n" );
document.write( "x=16/15 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );