document.write( "Question 8102: bill invested $30,000 in two seperate accounts paying 3% and 4.1% annual simple interest. if bill earned a total of of $1091.73 from the two investments, how much was invested in each account.\r
\n" ); document.write( "\n" ); document.write( "I have no clue how to come up with the equation of this problem. The instructions say to find the equation for this investments problem andsolve it. \n" ); document.write( "
Algebra.Com's Answer #4479 by srinivas123(23)\"\" \"About 
You can put this solution on YOUR website!
let one ammount be x then the second amount is 30000-x\r
\n" ); document.write( "\n" ); document.write( "Interest on first ammount i=ptr/100\r
\n" ); document.write( "\n" ); document.write( "(x*1*3 )/ 100. ----------------------equation (1)\r
\n" ); document.write( "\n" ); document.write( "Interest on second amount i=((30000-x)*1*4.1 )/ 100-------------equaion (2)\r
\n" ); document.write( "\n" ); document.write( "so total interest is equation (1) + (2)\r
\n" ); document.write( "\n" ); document.write( "3x/100 + 4.1(30000-x)/100 = 1091.73\r
\n" ); document.write( "\n" ); document.write( "after crossmultiplication we get
\n" ); document.write( "3x+4.1(30000-x)= 109173
\n" ); document.write( "3x+123000-4.1x = 109173\r
\n" ); document.write( "\n" ); document.write( "-1.1x = -13827\r
\n" ); document.write( "\n" ); document.write( "------> x=12570\r
\n" ); document.write( "\n" ); document.write( "hence first amount is $12570 and second amount is $17430.00.\r
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