document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64144>Question 64144</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Please help to : \r<BR>\n" );
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document.write( "Evaluate \r<BR>\n" );
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document.write( "a^2 - b^3(a - b)  if a = 1/3 and b = - 1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44787 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a^2 - b^3(a - b) [substitute:  a = 1/3 and b = - 1/2]<BR>\n" );
document.write( "(1/3)^2 - (-1/2)^3((1/3) - (-1/2)) [simplify]<BR>\n" );
document.write( "(1/9)+(1/8)(1/3+1/2)<BR>\n" );
document.write( "(1/9)+(1/8)(2+3/6)<BR>\n" );
document.write( "1/9+1/8(5/6)\r<BR>\n" );
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document.write( "1/9+5/48<BR>\n" );
document.write( "(48+45)/432 = 31/144<BR>\n" );
document.write( " </SPAN>\n" );
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