document.write( "Question 732388: A mixture of dried fruit and nuts sells for $4.30 per pound. Separately, the dried fruit sells for $2.50 per pound, and the nuts sell for $7.00 per pound. How much of each is needed to make 50 pounds of the mixture? \n" ); document.write( "

Algebra.Com's Answer #447843 by josgarithmetic(39617) $\"\"$ $\"About$

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This problem fits a very general two-part mixture situation. Here will be the beginning of a purely symbolic solution.\r
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\n" ); document.write( "\n" ); document.write( "L = $2.50/pound for the fruit
\n" ); document.write( "H = $7.00/pound for the nuts
\n" ); document.write( "T = $4.30/pound for the mixture
\n" ); document.write( "M = 50 pounds, quantity of the mixture
\n" ); document.write( "u = unknown pounds of fruit
\n" ); document.write( "v = unknown pounds of nuts\r
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\n" ); document.write( "\n" ); document.write( "Objective is to solve for u and v. A system of equations is necessary.\r
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\n" ); document.write( "\n" ); document.write( " $\"highlight%28%28Lu%2BHv%29%2FM=T%29\"$ and $\"highlight%28u%2Bv=M%29\"$
\n" ); document.write( "More than one way to start this solution process from here, but you could begin by doing a few operations on the T equation. It may be transformed to a linear equation of the two variables in standard for or general form, whichever you wish. Anyhow, you have two linear equations in two unknowns. Solve!\r
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\n" ); document.write( "\n" ); document.write( "Once solved for u and v, just substitute your given values to compute u and v. \n" ); document.write( "

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