document.write( "Question 732415: Find the equation with the given properties and sketch the graph-passes through the point of intersection of 2x+y-3=0 and x-y-3=0 and through the point (4,3). I am a bit lost on this: I've solved for each y intercepts (y=-2x-3 and y=x-3). Do I take the intersection of these two (2,-1) and do something like y=-x+1? This was done by looking at the graph, not performing the math...which I am unable to figure out-help. \n" ); document.write( "
Algebra.Com's Answer #447841 by stanbon(75887)\"\" \"About 
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Find the equation with the given properties and sketch the graph-passes through the point of intersection of 2x+y-3=0 and x-y-3=0 and through the point (4,3). I am a bit lost on this: I've solved for each y intercepts (y=-2x+3 and y=x-3).
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\n" ); document.write( "So: -2x+3 = x-3
\n" ); document.write( "3x = 6
\n" ); document.write( "x = 2
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\n" ); document.write( "And:
\n" ); document.write( "y = -2*2+3 = -1
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\n" ); document.write( "You want the equation of the line thru (2,-1) and (4,3)
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\n" ); document.write( "slope = (3--1)/(4-2) = 4/2 = 2
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\n" ); document.write( "Form: y = mx + b
\n" ); document.write( "Solve for \"b\":
\n" ); document.write( "3 = 2*4 + b
\n" ); document.write( "b = -5
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\n" ); document.write( "Equation:
\n" ); document.write( "y = 2x-5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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