document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64020>Question 64020</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395771161/algebrahomeworkh>Algebra Structure and method Book1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is 5cm. longeer than it is wide.If its length and width are both increased by 3 cm. its area is increased by 60 cm squared.Find the dimensions of the original rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44784 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangle is 5 cm. longer than it is wide.If its length and width are both increased by 3 cm. it's area is increased by 60 cm squared.Find the dimensions of the original rectangle.<BR>\n" );
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document.write( "Let x = width of the original rectangle<BR>\n" );
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document.write( "It states; \"rectangle is 5 cm. longer than it is wide.\" so we have:<BR>\n" );
document.write( "(x+5) = length of the original rectangle<BR>\n" );
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document.write( "Original rectangle is x by (x+5) so it's area = x(x+5) = (x^2 + 5x)<BR>\n" );
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document.write( "\"length and width are both increased by 3 cm.\" <BR>\n" );
document.write( "New Rectangle:<BR>\n" );
document.write( "Width = (x+3)<BR>\n" );
document.write( "Length = (x+5) + 3 = (x+8), <BR>\n" );
document.write( "New Rectangle area = (x+3)(x+8) = (x^2 + 11x + 24)<BR>\n" );
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document.write( "\"it's area is increased by 60 sq cm\" which means:<BR>\n" );
document.write( "New Rectangle area - Old rectangle area = 60<BR>\n" );
document.write( "(x^2 + 11x + 24) - (x^ + 5x) = 60<BR>\n" );
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document.write( "Remove the brackets, change the signs<BR>\n" );
document.write( "x^2 + 11x + 24 - x^2 - 5x = 60<BR>\n" );
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document.write( "Group like terms and do the math<BR>\n" );
document.write( "x^2 - x^2 + 11x - 5x + 24 = 60 <BR>\n" );
document.write( "6x + 24 = 60<BR>\n" );
document.write( "6x = 60 - 24<BR>\n" );
document.write( "x = 36/6<BR>\n" );
document.write( "x = 6 cm is the width of the original rectangle<BR>\n" );
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document.write( "6 + 5 = 11 cm is the length of the original rectangle<BR>\n" );
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document.write( "Check our solutions: old rectangle area 6*11, new rectangle area 9*14<BR>\n" );
document.write( "126 - 66 = 60 as stated<BR>\n" );
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document.write( "Did this make sense to you?? Any questions? </SPAN>\n" );
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