document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=732009>Question 732009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please solve and show all work. It would be greatly appreciated if you explained it too. Thanks.<BR>\n" );
document.write( "Divide:<BR>\n" );
document.write( "4x^2 - 3x + 2 / x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #447793 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=447793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you are dividing 4x^2 - 3x + 2 by x\r<BR>\n" );
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document.write( "divide 4x^2 by x to get 4x because x * 4x = 4x^2\r<BR>\n" );
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document.write( "subtract 4x^2 from 4x^2 - 3x + 2 to get -3x + 2\r<BR>\n" );
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document.write( "divide -3x by x to get -3 because -3 * x = -3x\r<BR>\n" );
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document.write( "subtract -3x from -3x + 2 to get + 2\r<BR>\n" );
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document.write( "since x is a higher order than 2 you are done dividing and 2 is your remainder.\r<BR>\n" );
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document.write( "your quotient is 4x - 3 + (2/x)\r<BR>\n" );
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document.write( "if you multiply that by x you will get back to 4x^2 - 3x + 2.\r<BR>\n" );
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