document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63878>Question 63878</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is to be no greater than 300 in., and the length must be 125 in.  Find the maximum width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44774 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44774\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the perimeter is not more than 300in:<BR>\n" );
document.write( "Perimeter <=300<BR>\n" );
document.write( "Using the formula for a perimeter: P=2(length+width), plug-in the values<BR>\n" );
document.write( "2(lenth+width)<=300 inches<BR>\n" );
document.write( "2(125+w)<=300 [solve for w]<BR>\n" );
document.write( "250+2w<=300<BR>\n" );
document.write( "2w<=300-250<BR>\n" );
document.write( "2w<=50<BR>\n" );
document.write( "w<=25 [any width larger or greater than 25 will not work]<BR>\n" );
document.write( ".<BR>\n" );
document.write( "checking:<BR>\n" );
document.write( "2(125+50)<=300<BR>\n" );
document.write( "2(175)<=300<BR>\n" );
document.write( "300<=300 [checks out]<BR>\n" );
document.write( ".<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );