document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=732280>Question 732280</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "the sum of ages of kelvin and paul is 50 years in five years time the age of paul will be four times the age of kelvin now. how old is each boys<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #447732 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=447732\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> K+P=50 OR K=50-P<BR>\n" );
document.write( "(K+5)=4P<BR>\n" );
document.write( "(50-P+5)=4P<BR>\n" );
document.write( "55-P=4P<BR>\n" );
document.write( "-4P-P=-55<BR>\n" );
document.write( "-5P=-55<BR>\n" );
document.write( "P=-55/-5<BR>\n" );
document.write( "P=11 PAUL IS 10 YEARS OLD NOW.<BR>\n" );
document.write( "K+11=50<BR>\n" );
document.write( "K=50-11=39 KEVIN'S AGE NOW.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "(39+5)=4*11<BR>\n" );
document.write( "44=44 </SPAN>\n" );
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