document.write( "Question 63957: PLEASE HELP...I AM STUCK ON WHAT TO DO HERE...I WOULD REALLY APPRECIATE YOUR HELP THANKS! \r
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document.write( "sketch the feasible region (quadrant 1 only) for the following system of linear inequalities\r
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document.write( "2x-6y< or equal to 0
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document.write( "9x-14y< or equal to 26
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document.write( "1x+3y< or equal to 53
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document.write( "-1+2y< or equal to 17
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document.write( "x> or equal to 0 and y > or equal to 0\r
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document.write( "SORRY I DON'T KNOW HOW TO WRITE THE EQUAL SIGN UNDER THE GREATER THAN OR LESS THAN SIGNS...I HOPE YOU UNDERSTAND WHAT I MEAN... \n" );
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Algebra.Com's Answer #44773 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! 2x-6y<= 0 [solve for y] \n" ); document.write( "-6y<=-2x \n" ); document.write( "y>=-2x/6 [switch the signs when multiplying or dividing by a negative number] \n" ); document.write( "y>=1/3x [draw the boundary line at y=1/3x. Use a solid line since the line is also 'equal to'.] \n" ); document.write( ". \n" ); document.write( "[shade all points greater than or equal to the line. that is, shade above or greater than the line]\r \n" ); document.write( "\n" ); document.write( " |