document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=732255>Question 732255</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "On a certain river, a paddleboat travels 24 miles upstream (against the current) in the same amount of time it travels 40 miles down stream (with the current.  If the current of the river is 4 miles per hour, determine the speed of the boat in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #447718 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=447718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "24=(R-4)T OR T=24/(R-4)<BR>\n" );
document.write( "40=(R+4)T OR T=40/(R+4)<BR>\n" );
document.write( "SET THESE TWO EQUATIONS EQUAL;<BR>\n" );
document.write( "24/(R-4)=40/(R+4) CROSS MULTIPLY.<BR>\n" );
document.write( "40(R-4)=24(R+4)<BR>\n" );
document.write( "40R-160=24R+96<BR>\n" );
document.write( "40R-24R=96+160<BR>\n" );
document.write( "16R=256<BR>\n" );
document.write( "R=256/16<BR>\n" );
document.write( "R=16 MPH. IS THE SPEED OF THE BOAT IN STILL WATER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "24/(16-4)=40/(16+4)<BR>\n" );
document.write( "24/12=40/20<BR>\n" );
document.write( "2=2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );