document.write( "Question 63886: Mr. Toya had part of his $5000 savings in an account that earned 7% interest and the rest in an account that earned 9% interest. How much did he have in each account if his annual from the total investment was $404.20? \n" ); document.write( "
Algebra.Com's Answer #44767 by stanbon(75887)\"\" \"About 
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Mr. Toya had part of his $5000 savings in an account that earned 7% interest and the rest in an account that earned 9% interest. How much did he have in each account if his annual from the total investment was $404.20?
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\n" ); document.write( "Let amount invested at 7% be x: interest in this is 0.07x dollars
\n" ); document.write( "Amount invested at 9% is \"5000-x\"; interest in this is 0.09(5000-x)=450-0.09x
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\n" ); document.write( "EQUATION:
\n" ); document.write( "interest + interest = 404.20
\n" ); document.write( "0.07x+450-0.09x=404.20
\n" ); document.write( "-0.02x=-45.8
\n" ); document.write( "x=$2290 (amount invest at 7%)
\n" ); document.write( "5000-x = 5000-3390=$2710 (amount invested at 9%)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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