document.write( "Question 732143: A train running between two towns arrives at its destination 10 minutes late when it
\n" ); document.write( "goes 40 miles per hour and 16 minutes late when it goes 30 miles per hour. The
\n" ); document.write( "distance between the two towns is \n" ); document.write( "
Algebra.Com's Answer #447570 by lwsshak3(11628)\"\" \"About 
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A train running between two towns arrives at its destination 10 minutes late when it
\n" ); document.write( "goes 40 miles per hour and 16 minutes late when it goes 30 miles per hour. The
\n" ); document.write( "distance between the two towns is.
\n" ); document.write( "***
\n" ); document.write( "x=on-time travel time
\n" ); document.write( "x+(1/6)=travel time at 40 mph
\n" ); document.write( "x+(4/15)=travel time at 30 mph
\n" ); document.write( "distance=travel time*speed
\n" ); document.write( "10 min=1/6 hr
\n" ); document.write( "16 min=16/60=4/15 hr
\n" ); document.write( "..
\n" ); document.write( "40(x+(1/6))=30(x+(4/15))
\n" ); document.write( "40x+40/6=30x+8
\n" ); document.write( "10x=8-40/6=48/6-40/6=8/6=4/3
\n" ); document.write( "x=4/30=2/15
\n" ); document.write( "40(x+(1/6))=40*.3=12
\n" ); document.write( "or
\n" ); document.write( "30(x+(4/15))=30*6/15=12\r
\n" ); document.write( "\n" ); document.write( "distance between the two towns is=12 mi \n" ); document.write( "
\n" );