document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=732120>Question 732120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cyclist rode the first 22-mile portion of his work at a constant speed. For the 14- mile cool down portion of his workout, he reduced his speed by 4 miles per hour. Each portion of the workout took the same time. Find the cyclist's speed during the first portion and find his speed during the cool down portion </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #447568 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=447568\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A cyclist rode the first 22-mile portion of his work at a constant speed. For the 14- mile cool down portion of his workout, he reduced his speed by 4 miles per hour. Each portion of the workout took the same time. Find the cyclist's speed during the first portion and find his speed during the cool down portion.<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=speed during first portion(22 mi)<BR>\n" );
document.write( "x-4=speed during cool down portion(14 mi)<BR>\n" );
document.write( "travel time=distance/speed<BR>\n" );
document.write( "..<BR>\n" );
document.write( "22/x=14/(x-4)<BR>\n" );
document.write( "14x=22x-88<BR>\n" );
document.write( "8x=88<BR>\n" );
document.write( "x=11<BR>\n" );
document.write( "x-4=7<BR>\n" );
document.write( "speed during first portion(22 mi)=11 mph<BR>\n" );
document.write( "speed during cool down portion(14 mi)=7 mph </SPAN>\n" );
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