document.write( "Question 732123: John and Mary leave their house at the same time and drive in opposite directions. John drives at 90 mi/h and travels 35 mi farther than Mary, who drives at 40 mi/h. Mary's trip takes 15 min longer than John's. For what length of time does each of them drive? \n" ); document.write( "
Algebra.Com's Answer #447564 by mananth(16946)![]() ![]() You can put this solution on YOUR website! john and Mary leave their house at the same time and drive in opposite directions. John drives at 90 mi/h and travels 35 mi farther than Mary, who drives at 40 mi/h. Mary's trip takes 15 min longer than John's. For what length of time does each of them drive?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let mary travel x miles \n" ); document.write( "john travels x+35 miles\r \n" ); document.write( "\n" ); document.write( "John speed = 90 mph \n" ); document.write( "Mary 40 mph\r \n" ); document.write( "\n" ); document.write( "Time Mary = x/40 \n" ); document.write( "Time john = (x+35)/90\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Time Mary -1/4 = Time John\r \n" ); document.write( "\n" ); document.write( "x/40 - 1/4 = (x+35)/90\r \n" ); document.write( "\n" ); document.write( "x/40-(x+35)/90 = 1/4\r \n" ); document.write( "\n" ); document.write( "90x-40(x+35)= 900\r \n" ); document.write( "\n" ); document.write( "90x-40x-1400=900\r \n" ); document.write( "\n" ); document.write( "90x-40x-1400=900\r \n" ); document.write( "\n" ); document.write( "50x=2300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=46 miles\r \n" ); document.write( "\n" ); document.write( "John time = (46+35)/90 = 0.9 hours \n" ); document.write( "Mary time = 46/40=1.15 hours\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |