document.write( "Question 732013: A plane is flying the 2553mile trip from los Angeles to Holohulu into a 60 mph headwind.if the speed of the plane in still air is 310mph.How far from Los Angeles is the plane's point of no retutn \n" ); document.write( "
Algebra.Com's Answer #447548 by mananth(16946)\"\" \"About 
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given information
\n" ); document.write( " 310 + 60 = 370 mph speed with the wind
\n" ); document.write( " 310 - 60 - 250 mph speed against the wind
\n" ); document.write( " :
\n" ); document.write( " Let d = dist to LA from point of no return
\n" ); document.write( " Then
\n" ); document.write( " (2553-d) = dist to Honolulu from point of no return
\n" ); document.write( " :
\n" ); document.write( " : Time = dist/speed
\n" ); document.write( " :
\n" ); document.write( " Return to LA= Continue to Honolulu time
\n" ); document.write( "d/360 = 2553-d/250\r
\n" ); document.write( "\n" ); document.write( " Cross multiply:
\n" ); document.write( " 250d = 360(2553-d)
\n" ); document.write( " :
\n" ); document.write( " 250d = 919080 - 360d
\n" ); document.write( " :
\n" ); document.write( " 610d = 919080
\n" ); document.write( " d = 1506.69
\n" ); document.write( " Check solution by finding the distance to LA and calculating the time to both:
\n" ); document.write( " 2553-1506.69= = 1046.31 mi Honolulu
\n" ); document.write( " :
\n" ); document.write( " Time to L A: 1506.69/360 = 4.19 hrs
\n" ); document.write( " Time to Honolulu: 1046.31/250 = 4.19 hrs \r
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