document.write( "Question 732113: an investor invested a total of 2700 dollars in two mutual funds. one funded 5% and the other at 2% profit.if the investors total profit was $93 how much was invested in each mutual fund \n" ); document.write( "
Algebra.Com's Answer #447534 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 2.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 5.00% per annum ------------ Amount invested = y \n" ); document.write( " 2700 \n" ); document.write( "Interest----- 93.00 \n" ); document.write( " \n" ); document.write( "Part I 2.00% per annum ---x \n" ); document.write( "Part II 5.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 2700 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "2.00% x + 5.00% y= 93 \n" ); document.write( "Multiply by 100 \n" ); document.write( "2 x + 5 y= 9300.00 --------2 \n" ); document.write( "Multiply (1) by -2 \n" ); document.write( "we get \n" ); document.write( "-2 x -2 y= -5400.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x 3 y= 3900 \n" ); document.write( "divide by 3 \n" ); document.write( " y = 1300 \n" ); document.write( "Part I 2.00% $ 1400 \n" ); document.write( "Part II 5.00% $ 1300 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "1400 --------- 2.00% ------- 28.00 \n" ); document.write( "1300 ------------- 5.00% ------- 65.00 \n" ); document.write( "Total -------------------- 93.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |