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document.write( "A is 27 years old. B is one third older. How many years ago was the ratio of A's age to B's age equal to 4:7? \n" );
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Algebra.Com's Answer #447488 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! 4/7=(A-X)/(B-X) \n" ); document.write( "4/7=(27-X)/(27+9-X) CROSS MULTIPLY. \n" ); document.write( "7(27-X)=4(36-X) \n" ); document.write( "189-7X=144-4X \n" ); document.write( "-7X+4X=144-189 \n" ); document.write( "-3X=-45 \n" ); document.write( "X=-45/-3 \n" ); document.write( "X=15 YEARS AGE THEIR AGES WERE 4:7 \n" ); document.write( "PROOF: \n" ); document.write( "(27-15)/(36-15) \n" ); document.write( "12/21=4/7 \n" ); document.write( "12*7=21*4 \n" ); document.write( "84=84 \n" ); document.write( " \n" ); document.write( " |