document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=732063>Question 732063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Freddie leaves home and rides his bicycle out into the country for 2.7 hours. On his return trip along the same route, it takes him 0.9 of an hour longer. If his rate on the return trip was 3 miles per hour slower than on the trip out into the country, find the total round trip distance.\r<BR>\n" );
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document.write( "I have asked everyone in my class and no one knows how to get the answer. Instructor is unavailable until Monday. PLEASE HELP!! :) Thank you in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #447475 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=447475\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "D=R*2.7<BR>\n" );
document.write( "D=(R-3)(2.7+.9)<BR>\n" );
document.write( "2.7R=(R-3)*3.6<BR>\n" );
document.write( "2.7R=3.6R-10.8<BR>\n" );
document.write( "2.7R-3.6R=-10.8<BR>\n" );
document.write( "-.9R=-10.8<BR>\n" );
document.write( "R=-10.8/-.9<BR>\n" );
document.write( "R=12 MPH IS THE RATE ON THE OUT TRIP.<BR>\n" );
document.write( "D=12*2.7=32.4 MILES ID THE DISTACE OUT.<BR>\n" );
document.write( "D=(12-3)(2.7+.9)<BR>\n" );
document.write( "D=9*3.6=32.4 DITTO.<BR>\n" );
document.write( "2*32.4=64.8 MILES FOR THE ROUND TRIP DIDTANCE.<BR>\n" );
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