document.write( "Question 732069:
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document.write( "Suppose that one solution contains 20% alcohol and another solution contains 50% alcohol. How many liter of each solution should be mixed to make 12 liters of a 40% solution? \n" );
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Algebra.Com's Answer #447469 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .50X+.20(12-X)=.40*12 \n" ); document.write( ".50X+2.4-.20X=4.8 \n" ); document.write( ".30X=4.8-2.4 \n" ); document.write( ".30X=2.4 \n" ); document.write( "X=2.4/.30 \n" ); document.write( "X=8 LITERS OF 50% SOLUTION IS USED. \n" ); document.write( "12-8=4 LITERS OF 20% SOLUTION IS USED. \n" ); document.write( "PROOF: \n" ); document.write( ".50*8+.20*4=.40*12 \n" ); document.write( "4+.8=4.8 \n" ); document.write( "4.8=4.8 \n" ); document.write( " |