document.write( "Question 732069:
\n" ); document.write( "Suppose that one solution contains 20% alcohol and another solution contains 50% alcohol. How many liter of each solution should be mixed to make 12 liters of a 40% solution?
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Algebra.Com's Answer #447469 by checkley79(3341)\"\" \"About 
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.50X+.20(12-X)=.40*12
\n" ); document.write( ".50X+2.4-.20X=4.8
\n" ); document.write( ".30X=4.8-2.4
\n" ); document.write( ".30X=2.4
\n" ); document.write( "X=2.4/.30
\n" ); document.write( "X=8 LITERS OF 50% SOLUTION IS USED.
\n" ); document.write( "12-8=4 LITERS OF 20% SOLUTION IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".50*8+.20*4=.40*12
\n" ); document.write( "4+.8=4.8
\n" ); document.write( "4.8=4.8
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