document.write( "Question 731976: a daughters age is 32 years younger than her farther. In 4 years, the farther will be 5 times as old as hid daughter. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #447416 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a daughters age is 32 years younger than her father. In 4 years, the father will be 5 times as old as his daughter. How old is each now? \n" ); document.write( "----- \n" ); document.write( "Equations: \n" ); document.write( "d = f-32 \n" ); document.write( "(f+4) = 5(d+4) \n" ); document.write( "----- \n" ); document.write( "Substitute for \"d\" and solve for \"f\": \n" ); document.write( "f+4 = 5(f-32+4) \n" ); document.write( "f+4 = 5(f-28) \n" ); document.write( "f+4 = 5f-140 \n" ); document.write( "4f = 144 \n" ); document.write( "father's age = 144/4 = 36 \n" ); document.write( "----- \n" ); document.write( "Solve for \"d\": \n" ); document.write( "daughter's age = 36-32 = 4 \n" ); document.write( "============ \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |