document.write( "Question 731976: a daughters age is 32 years younger than her farther. In 4 years, the farther will be 5 times as old as hid daughter. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #447416 by stanbon(75887)\"\" \"About 
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a daughters age is 32 years younger than her father. In 4 years, the father will be 5 times as old as his daughter. How old is each now?
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\n" ); document.write( "Equations:
\n" ); document.write( "d = f-32
\n" ); document.write( "(f+4) = 5(d+4)
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\n" ); document.write( "Substitute for \"d\" and solve for \"f\":
\n" ); document.write( "f+4 = 5(f-32+4)
\n" ); document.write( "f+4 = 5(f-28)
\n" ); document.write( "f+4 = 5f-140
\n" ); document.write( "4f = 144
\n" ); document.write( "father's age = 144/4 = 36
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\n" ); document.write( "Solve for \"d\":
\n" ); document.write( "daughter's age = 36-32 = 4
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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