document.write( "Question 731918: Perform the indicated operation (2x^3+x^2-x+1) / (2x+3) (use long division) \n" ); document.write( "
Algebra.Com's Answer #447410 by josgarithmetic(39618)\"\" \"About 
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2x^3/(2x) = x^2.
\n" ); document.write( "x^2*(2x+3)=2x^3+3x^2.
\n" ); document.write( "Subtraction gives -2x^2; bring down -x.
\n" ); document.write( "Look at -2x^2-x.\r
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\n" ); document.write( "\n" ); document.write( "-2x^2/(2x)=-x
\n" ); document.write( "-x*(2x+3)=-2x^2-3x.
\n" ); document.write( "Subtraction gives 2x; bring down the 1.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(2)/().... This 2x+1 looks like a remainder.\r
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\n" ); document.write( "\n" ); document.write( "Quotient without remainder is \"x%5E2-x\", and remainder is \"%282x%2B1%29%2F%282x%2B3%29\".
\n" ); document.write( "Continued for one more step, quotient is x^2-x+1, remainder -2. This should mean, \"x%5E2-x%2B1-2%2F%282x%2B3%29\".
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