document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=731885>Question 731885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is six times its width. If the area of the rectangle is 486 cm^2 , find its perimeter.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #447403 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=447403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=6W<BR>\n" );
document.write( "A=L*W<BR>\n" );
document.write( "486=6W*W<BR>\n" );
document.write( "486=6W^2<BR>\n" );
document.write( "W^2=486/6<BR>\n" );
document.write( "W^2=81<BR>\n" );
document.write( "W=SQRT81<BR>\n" );
document.write( "W=9 cm ANS. FOR THE WIDTH.<BR>\n" );
document.write( "L=6*9=54 cm ANS. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "9*54=486<BR>\n" );
document.write( "496=496<BR>\n" );
document.write( "P=2L+2W<BR>\n" );
document.write( "P=2*54+2*9<BR>\n" );
document.write( "P=108+18=126 cm ANS. FOR THE PERIMETER. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );