document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63979>Question 63979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Work backward to solve.\r<BR>\n" );
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document.write( "Manuel's term paper is due on MArch 31.  He began doing reasearch on March 1.  He intends to continue doing reasearch for 3 times as long as he has done already.  Then he will spend a week writing the paper and the remaining 3 days typing.  What day is it? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44737 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44737\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the term paper is due on March 31 then it needs to be completed on March 30. If typing will take 3 days then it needs to be written by March 27. If it takes a week to be written then research must have finished on March 20. <BR>\n" );
document.write( "If this is day x and three times as much research needs to be done then 3x days of research remain. The total number of days will be 4x=20 so x = 5.<BR>\n" );
document.write( "Today must be March 5 with 15 days research still to be done. </SPAN>\n" );
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