document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=731897>Question 731897</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor by grouping. <BR>\n" );
document.write( "50x2 – 50x – 12  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #447364 by </B><A HREF=/tutors/aboutme.mpl?userid=Abdul+Hannan><B>Abdul Hannan(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Abdul+Hannan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=447364\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 50x² - 50x - 12\r<BR>\n" );
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document.write( "we first take the product of  the co-efficient of x² and the constant term and start grouping them in pairs such that the sum of their factors is -50\r<BR>\n" );
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document.write( "50*(-12) = 600\r<BR>\n" );
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document.write( "50*(-12) can also be written as 5*(-120) whose sum of the factors is 5+(-120) = -115 not equal to -50\r<BR>\n" );
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document.write( "50*(-12) = 10*(-60) whose sum of the factors is 10+(-60) = -50 (bingo)\r<BR>\n" );
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document.write( "hence we group the expression as<BR>\n" );
document.write( "50x2 + (10-60)x - 12\r<BR>\n" );
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document.write( "50x2 + 10x - 60x - 12\r<BR>\n" );
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document.write( "10x(5x+1) - 12(5x+1)\r<BR>\n" );
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document.write( "(10x-12)*(5x+1)\r<BR>\n" );
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document.write( "It can be further resolved taking 2 out of the brackets as a common factor<BR>\n" );
document.write( "2*(5x-6)*(5x+1) </SPAN>\n" );
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