document.write( "Question 64049: 3x + 4y = 12 (0, ),( ,3/4),( ,0),(8/3, ) \n" ); document.write( "
Algebra.Com's Answer #44735 by funmath(2933)\"\" \"About 
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3x + 4y = 12 (0, ),( ,3/4),( ,0),(8/3, )
\n" ); document.write( "Ordered pairs are in this order (x,y)
\n" ); document.write( "For (0, ), let x=0 and solve for y.
\n" ); document.write( "3(0)+4y=12
\n" ); document.write( "0+4y=12
\n" ); document.write( "4y=12
\n" ); document.write( "4y/4=12/4
\n" ); document.write( "y=3
\n" ); document.write( "Therefore, (x,y)=(0,3)
\n" ); document.write( ":
\n" ); document.write( "For ( ,3/4), let y=3/4 and solve for x.
\n" ); document.write( "3x+4(3/4)=12
\n" ); document.write( "3x+12/4=12
\n" ); document.write( "3x+3=12
\n" ); document.write( "3x+3-3=12-3
\n" ); document.write( "3x=9
\n" ); document.write( "3x/3=9/3
\n" ); document.write( "x=3
\n" ); document.write( "Therefore, (x,y)=(3,3/4)
\n" ); document.write( ":
\n" ); document.write( "For ( ,0), let y=0 and solve for x.
\n" ); document.write( "3x+4(0)=12
\n" ); document.write( "3x+0=12
\n" ); document.write( "3x=12
\n" ); document.write( "3x/3=12/3
\n" ); document.write( "x=4
\n" ); document.write( "Therefore, (x,y)=(4,0)
\n" ); document.write( ":
\n" ); document.write( "For (8/3, ), let x=8/3 and solve for y.
\n" ); document.write( "3(8/3)+4y=12
\n" ); document.write( "24/3+4y=12
\n" ); document.write( "8+4y=12
\n" ); document.write( "8-8+4y=12-8
\n" ); document.write( "4y=4
\n" ); document.write( "4y/4=4/4
\n" ); document.write( "y=1
\n" ); document.write( "Therefore, (x,y)=(8/3,1)
\n" ); document.write( "Happy Calculating!!!
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