document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=731867>Question 731867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do i work this one out and then factor it?  please help.\r<BR>\n" );
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document.write( "4(a + 3)2 – (a + 3) – 18 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #447325 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=447325\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do i work this one out and then factor it?  please help.\r<BR>\n" );
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document.write( "4(a + 3)2 – (a + 3) – 18<BR>\n" );
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document.write( "I don't know what you mean by \"work this one out,\" but it can be factored<BR>\n" );
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document.write( "Use ^ (Shift 6) for exponents<BR>\n" );
document.write( "4(a + 3)^2 – (a + 3) – 18<BR>\n" );
document.write( "sub x for (a+3) temporarily<BR>\n" );
document.write( "4x^2 – x – 18<BR>\n" );
document.write( "It will be either (x + m)*(4x + n) or (2x + m)*(2x + n)<BR>\n" );
document.write( "Since the x term has an odd coefficent, it can't be (2x + m)*(2x + n).<BR>\n" );
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document.write( "It will be (x + m)*(4x + n)<BR>\n" );
document.write( "Find a pair of factors of 18 that fit.<BR>\n" );
document.write( "The signs will be different since it's -18<BR>\n" );
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document.write( "18 has 3 pairs of factors<BR>\n" );
document.write( "1*18<BR>\n" );
document.write( "2*9<BR>\n" );
document.write( "3*6<BR>\n" );
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document.write( "(x + m)*(4x + n)<BR>\n" );
document.write( "The n has to be the odd number, so it's 1, 3 or 9 (either + or minus)<BR>\n" );
document.write( "Now it's trial and error.<BR>\n" );
document.write( "(x + 2)*(4x - 9) works<BR>\n" );
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document.write( "Sub back (a+3) for x<BR>\n" );
document.write( "= (a+3+2)*(4a+12-9)<BR>\n" );
document.write( "= (a+5)*(4a+3)<BR>\n" );
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document.write( "You can expand 4(a + 3)^2 – (a + 3) – 18 first<BR>\n" );
document.write( "= 4a^ + 24a + 36 - a - 3 - 18<BR>\n" );
document.write( "= 4a^2 + 23a + 15<BR>\n" );
document.write( "That might be slightly easier since it's all positive numbers.<BR>\n" );
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