document.write( "Question 731857: An object is thrown upward from the top of a 96-foot building with an initial velocity of 80 per second. The height h of the object after t is given by the quadratic equation h=16t+80t+96\r
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Algebra.Com's Answer #447309 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The equation should be:
\n" ); document.write( "\"+h%28t%29+=+-16t%5E2+%2B+80t+%2B+96+\"
\n" ); document.write( "The object will hit the ground when
\n" ); document.write( "\"+h%28t%29+=+0+\" , so
\n" ); document.write( "\"+0+=+-16t%5E2+%2B+80t+%2B+96+\"
\n" ); document.write( "Divide both sides by \"+16+\"
\n" ); document.write( "\"+0+=+-t%5E2+%2B+5t+%2B+6+\"
\n" ); document.write( "Using the quadratic equation:
\n" ); document.write( "\"+t+=+%28-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29+\"
\n" ); document.write( "\"+a+=+-1+\"
\n" ); document.write( "\"+b+=+5+\"
\n" ); document.write( "\"+c+=+6+\"
\n" ); document.write( "\"+t+=+%28-5+%2B-+sqrt%28+5%5E2+-+4%2A%28-1%29%2A6+%29%29+%2F+%282%2A%28-1%29%29+\"
\n" ); document.write( "\"+t+=+%28-5+%2B-+sqrt%28+25+%2B+24+%29%29+%2F+%28-2%29+\"
\n" ); document.write( "\"+t+=+%28-5+%2B-+sqrt%28+49+%29%29+%2F+%28-2%29+\"
\n" ); document.write( "\"+t+=+%28+-5+-+7+%29+%2F+%28-2%29+\" ( can't use the (+) square root, gives negative t )
\n" ); document.write( "\"+t+=+6+\"
\n" ); document.write( "The object hits the ground in 6 sec
\n" ); document.write( "Here's the plot:
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-2%2C+7%2C+-10%2C+220%2C+-16x%5E2+%2B+80x+%2B+96+%29+\"
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