document.write( "Question 731797: Find a polynomial f(x) of degree 3 that has the indicated zeros and satisfies the given condition.\r
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document.write( "-1, -3, 0; f(-2) = -8\r
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document.write( "I have tried this:\r
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document.write( "(x+1)(x+3)(x+0)
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document.write( "=(x+0)(x^2+4x+3)
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document.write( "=x^3+4x^2+3x\r
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document.write( "then
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document.write( "f(-8)=a(-2+1)(-2+3)(-2+0)
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document.write( "=f(-8)=a(-1)(1)(-2)
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document.write( "-8=a-2
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document.write( "a=4\r
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document.write( "so then I combine the two, and I get:\r
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document.write( "4(x^3+4x^2+3x)
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document.write( "=4x^3+16x^2+12x
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document.write( "and I divide by 4x, I get:\r
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document.write( "4x(x^2+4x+3) and I simplify that to:\r
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document.write( "4x(x+1)(x+3)\r
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document.write( "but the answer is wrong. Any idea what I did wrong? \n" );
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Algebra.Com's Answer #447298 by Alan3354(69443) You can put this solution on YOUR website! Find a polynomial f(x) of degree 3 that has the indicated zeros and satisfies the given condition. \n" ); document.write( "-1, -3, 0; f(-2) = -8 \n" ); document.write( "I have tried this: \n" ); document.write( "(x+1)(x+3)(x+0) \n" ); document.write( "=(x+0)(x^2+4x+3) \n" ); document.write( "=x^3+4x^2+3x \n" ); document.write( "then \n" ); document.write( "f(-8)=a(-2+1)(-2+3)(-2+0) ************ f(-2), not f(-8) \n" ); document.write( "--------- \n" ); document.write( "f(-2) = -8 + 16 - 6 = 2 \n" ); document.write( "-------- \n" ); document.write( "--> (-3)*(x^3+4x^2+3x) \n" ); document.write( "f(x) = -3x^3 - 12x^2 - 9x \n" ); document.write( " \n" ); document.write( " |