document.write( "Question 731801: √(x+10)=2-x
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\n" ); document.write( "√(x+3)=(x-1)/3
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Algebra.Com's Answer #447288 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%28x%2B10%29=2-x\"\r
\n" ); document.write( "\n" ); document.write( "Square both sides and simplify. Simplify means get all terms on one side and just 0 on the other side, and make terms in the order of general form, decreasing degree of x. \r
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\n" ); document.write( "\n" ); document.write( "Those instructions might be a little too brief, so here is a refinement:\r
\n" ); document.write( "\n" ); document.write( "The right hand member contains a variable and a constant term. The left hand member uses the variable term and a constant term both inside the square root function. We want to unwrap the left hand member, so we start by squaring BOTH sides.\r
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\n" ); document.write( "\n" ); document.write( "(1) Square both sides.
\n" ); document.write( "\"%28sqrt%28x%2B10%29%29%5E2=%282-x%29%5E2\"
\n" ); document.write( "\"x%2B10=4-4x%2Bx%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "(2) Use inverse operations to collect the terms to one side and have zero on the other side; we can detect by visual inspection that we'll have a quadratic equation.
\n" ); document.write( "\"x%5E2-4x%2B4=x%2B10\"
\n" ); document.write( "\"x%5E2-5x-6=0\"\r
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\n" ); document.write( "\n" ); document.write( "(3) If you are interested in solving for x, you'd either use factoring or general solution to quadratic equation.
\n" ); document.write( "See if the quadratic expression is easy to factor first...
\n" ); document.write( "?*?=-6, ?+?=-5
\n" ); document.write( "-6*1=-6, -6+1=-5, that is the pair of constants for the linear binomials.
\n" ); document.write( "\"x%5E2-5x-6\"=\"%28x-6%29%28x%2B1%29=0\"
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