document.write( "Question 731786: solve using Applications of a non linear system
\n" ); document.write( "Find the length and width of a rectangle whose perimeter is 20 feet and whose area is 21 square feet
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Algebra.Com's Answer #447274 by stanbon(75887)\"\" \"About 
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Find the length and width of a rectangle whose perimeter is 20 feet and whose area is 21 square feet
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\n" ); document.write( "20 = 2(L + W)
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\n" ); document.write( "L*W = 21
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\n" ); document.write( "Equation:
\n" ); document.write( "L + W = 10
\n" ); document.write( "L*W = 21
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\n" ); document.write( "Substitute for \"L\" and solve for \"W\"
\n" ); document.write( "(10-W)W = 21
\n" ); document.write( "10W - W^2 = 21
\n" ); document.write( "W^2 - 10W + 21 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "(W-3)(W-7) = 0
\n" ); document.write( "Width = 3 or Width = 7
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\n" ); document.write( "If Width = 3, then Length = 7
\n" ); document.write( "If Width = 7 then Length = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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