document.write( "Question 731700: Hi,
\n" ); document.write( "Can someone tell me the steps how to solve this\r
\n" ); document.write( "\n" ); document.write( "cox x + 1 = √3 sin x where 0 ≤ x < 2∏\r
\n" ); document.write( "\n" ); document.write( "the answer is cos x = 1/2 or cos x =-1\r
\n" ); document.write( "\n" ); document.write( "I just want to know how did they get it.\r
\n" ); document.write( "\n" ); document.write( "Thank you so much in advance.
\n" ); document.write( "

Algebra.Com's Answer #447245 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
cos x + 1 = √3 sin x where 0 ≤ x < 2π
\n" ); document.write( "cos x + 1 = √3 sin x
\n" ); document.write( "square both sides
\n" ); document.write( "cos^2x+2cosx+1=3sin^2x
\n" ); document.write( "cos^2x+2cosx+1=3(1-cos^2x)
\n" ); document.write( "cos^2x+2cosx+1=3-3cos^2x)
\n" ); document.write( "4cos^2x+2cosx-2=0
\n" ); document.write( "(4cosx-2)(cosx+1)=0
\n" ); document.write( "..
\n" ); document.write( "4cosx-2=0
\n" ); document.write( "cosx=1/2
\n" ); document.write( "x=π/3, 5π/3 (In quadrants I and IV where cos>0)
\n" ); document.write( "or
\n" ); document.write( "cosx+1=0
\n" ); document.write( "cosx=-1
\n" ); document.write( "x=π
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