document.write( "Question 731574: Suppose you deposit $500 in an account with an annual interest rate of 8% compounded monthly.\r
\n" ); document.write( "\n" ); document.write( "a. Find an equation that gives the amount of money in the account after t years.
\n" ); document.write( "b. Find the amount of money in the account after 5 years.
\n" ); document.write( "c. How many years will it take for the account to contain $1000?
\n" ); document.write( "d. If the interest were compounded continuously, how much money would the account contain after 5 years?\r
\n" ); document.write( "\n" ); document.write( "Thank You So Much!
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Algebra.Com's Answer #447240 by KMST(5328)\"\" \"About 
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Interest compounded monthly:
\n" ); document.write( "The interest for 1 month would be \"1%2F12\" of 8%, meaning \"%281%2F12%29%288%2F100%29+=2%2F300\" of the initial balance that month.
\n" ); document.write( "So at the end of the first month you would have a balance (in $) of
\n" ); document.write( "\"500%2B500%282%2F300%29=500%2B500%2A2%2F300=500%281%2B2%2F300%29\"
\n" ); document.write( "So the new balance would be the initial balance times \"%281%2B2%2F300%29\" .
\n" ); document.write( "
\n" ); document.write( "During the second month, you would be earning interest on the whole of that $\"500%281%2B2%2F300%29\" and that balance would be multiplied times \"%281%2B2%2F300%29\" to get the new balance of
\n" ); document.write( "\"500%281%2B2%2F300%29%281%2B2%2F300%29=500%2A%281%2B2%2F300%29%5E2\"
\n" ); document.write( "
\n" ); document.write( "After \"n\" months you would have a total of
\n" ); document.write( "$\"500%2A%281%2B2%2F300%29%5En\"
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\n" ); document.write( "a. At the end of 5 years you would have accumulated interest during \"5%2A%2812months%29=60months\" and would have a total of
\n" ); document.write( "$\"500%2A%281%2B2%2F300%29%5E60\"= $\"774.92\" (rounded)
\n" ); document.write( "
\n" ); document.write( "b. To get to \"500%2A%281%2B2%2F300%29%5En=1000\" you will need \"n\" months, and we can find \"n\" like this:
\n" ); document.write( "From
\n" ); document.write( "\"500%2A%281%2B2%2F300%29%5En=1000\"
\n" ); document.write( "taking logarithms on both sides, we get
\n" ); document.write( "\"log%28%28500%2A%281%2B2%2F300%29%5En%29%29=log%28%281000%29%29\" --> \"log%28%28500%29%29%2Bn%2Alog%28%281%2B2%2F300%29%29=3\" --> \"n=%283-log%28%28500%29%29%29%2Flog%28%281%2B2%2F300%29%29\"
\n" ); document.write( "That calculates as about \"104.3\" (rounded)
\n" ); document.write( "If you need $1000, you will have to wait for 105 months because
\n" ); document.write( "after 104 months you will have
\n" ); document.write( "$\"500%2A%281%2B2%2F300%29%5E104\"= $\"997.89\" (rounded)
\n" ); document.write( "but after 105 months you will have
\n" ); document.write( "$\"500%2A%281%2B2%2F300%29%5E105\"= $\"1004.54\" (rounded)
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\n" ); document.write( "c. Interest compounded monthly:
\n" ); document.write( "If the interest was calculated and added to the balance after shorter and shorter periods, you would gain a little bit more as the periods were shortened, getting as close as you want, but never going over a certain limit.
\n" ); document.write( "That limit is what they call continuous compounding.
\n" ); document.write( "The balance with continuous compounding is given by the function
\n" ); document.write( "\"balance\"= $\"500%2Ae%5E%280.08%2Ay%29\" with \"y\"= number of years.
\n" ); document.write( "In that expression,
\n" ); document.write( "$\"500\" is the initial deposit,
\n" ); document.write( "\"0.08\" is the 8% interest rate expresed as a decimal,
\n" ); document.write( "and \"e\" is an irrational number, like \"pi\".
\n" ); document.write( "For \"y=5\" we get the balance after 5 years as
\n" ); document.write( "$\"500%2Ae%5E%280.08%2A5%29\"= $\"500%2Ae%5E0.4\"= $\"745.91\"
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