document.write( "Question 731662: when logx=2logA-(1/2)logB, x is equal to \n" ); document.write( "
Algebra.Com's Answer #447235 by nerdybill(7384)\"\" \"About 
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when logx=2logA-(1/2)logB, x is equal to
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\n" ); document.write( "logx=2logA-(1/2)logB
\n" ); document.write( "logx = logA^2 - logB^(1/2)
\n" ); document.write( "logx = log(A^2/B^(1/2))
\n" ); document.write( "x = A^2/B^(1/2)
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\n" ); document.write( "or,
\n" ); document.write( "\"x+=+A%5E2%2FB%5E%281%2F2%29\"
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\n" ); document.write( "\"x+=+A%5E2%2Fsqrt%28B%29\"
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\n" ); document.write( "\"x+=+A%5E2%2Fsqrt%28B%29%2A+sqrt%28B%29%2Fsqrt%28B%29\"
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\n" ); document.write( "\"x+=+A%5E2%2Asqrt%28B%29%2FB\"\r
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