document.write( "Question 731432: What five different whole numbers add up to 18 multiply those same numbers and get 240? \n" ); document.write( "
Algebra.Com's Answer #447229 by KMST(5328)\"\" \"About 
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THE ANSWER:
\n" ); document.write( "\"highlight%281%2B2%2B4%2B5%2B6=18%29\" \"highlight%281%2A2%2A4%2A5%2A6=240%29\"
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\n" ); document.write( "HOW TO GET TO THE ANSWER:
\n" ); document.write( "We need to find factors of 240.
\n" ); document.write( "Either systematically or sloppily.
\n" ); document.write( "Systematically:
\n" ); document.write( "\"240=2%5E4%2A3%2A5\" prime factorization that can be obtained by dividing over and over by prime numbers in order, starting from 2 and going up:
\n" ); document.write( "240 ÷ \"red%282%29\" = 120
\n" ); document.write( "120 ÷ \"red%282%29\" = 60
\n" ); document.write( "60 ÷ \"red%282%29\" = 30
\n" ); document.write( "30 ÷ \"red%282%29\" = 15
\n" ); document.write( "15 ÷ \"red%283%29\" = \"red%285%29\"
\n" ); document.write( "So 240 = \"red%282%29\"X\"red%282%29\"X\"red%282%29\"X\"red%282%29\"X\"red%283%29\"X\"red%285%29\"
\n" ); document.write( "The sloppy way:
\n" ); document.write( "I know that 240 = 30 X 8, so
\n" ); document.write( "\"24=8%2A30=8%2A10%2A3=8%2A2%2A5%2A3=2%2A2%2A2%2A2%2A5%2A3\"
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\n" ); document.write( "Then, it's a question of turning the 6 factors in \"2%2A2%2A2%2A2%2A3%2A5\" into five factors by grouping (multiplying) some together, and maybe including a 1 as a factor.
\n" ); document.write( "If we do not include a 1, to add up to the even number 18, we could have both odd factors (3 and 5) by themselves, adding to 12, or both paired with a 2, to become even numbers.
\n" ); document.write( "Neither choice works.
\n" ); document.write( "With 3 and 5 as two of the five different whole numbers, we have
\n" ); document.write( "\"3%2B5=8\" and the four remaining 2's cannot be grouped into the three additional different whole numbers.
\n" ); document.write( "Using \"2%2A3=6\" and \"2%2A5=10\" as two of the five different whole numbers is not possible either, because we would just have two extra 2's to make three additional whole numbers from.
\n" ); document.write( "With \"blue%281%29\" as one of the five different whole numbers, what would we do with \"3\" and \"5\"?
\n" ); document.write( "We need one and only one additional odd number.
\n" ); document.write( "The other odd number must be turned into an even number by grouping it with a 2.
\n" ); document.write( "We would be left with three 2's to be turned into the two additional different whole numbers.
\n" ); document.write( "Those two additional different whole numbers can only be \"blue%282%29\" and \"2%2A2=blue%284%29\"
\n" ); document.write( "What do we do with \"3\" and \"5\"?
\n" ); document.write( "\"2%2A3=blue%286%29\" and \"blue%285%29\" as two of the five different whole numbers is an obvious choice, because using \"2%2A5=10\" and \"3\" would make the sum too large:
\n" ); document.write( "\"1%2B3%2B10%2B2%2B4=14%2B2%2B4=20\".
\n" ); document.write( "So \"highlight%28blue%281%29%29\", \"highlight%28blue%282%29%29\", \"highlight%28blue%284%29%29\", \"highlight%28blue%285%29%29\", and \"highlight%28blue%286%29%29\" are the five different whole numbers that multiply to yield 240,
\n" ); document.write( "\"highlight%281%2A2%2A4%2A5%2A6=240%29\",
\n" ); document.write( "and
\n" ); document.write( "\"highlight%281%2B2%2B4%2B5%2B6=18%29\" is the 5-number sum.
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