document.write( "Question 731652: how do we work out how to find the answers to all these question i have tried but i get different to the answers in the book and my son is in tears....\r
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document.write( "pumpa can fill a tank in 5 mins while pump b can fill a tank in 10 mins. how long will it take to fill the tank if both are working together?\r
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document.write( "b/
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document.write( "in making one revolution a car wheel travels 200cm . how fast are the wheels spinngin in revolutions per minute, when the car is travelling at 60km/h?\r
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document.write( "a girl paddles her kayak upstream from her home to her friends home takin 2.5 hours for the journedy. sher returns taht afternoon in 1.5 hrs .
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document.write( "if the is flowing at 2.5 km/h find:
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document.write( "1/ her paddling speed in still water
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document.write( "2/ the distance to ther friends place. \n" );
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Algebra.Com's Answer #447218 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! pump a can fill a tank in 5 mins while pump b can fill a tank in 10 mins \n" ); document.write( "how long will it take to fill the tank if both are working together? \n" ); document.write( ": \n" ); document.write( "let m = no. of minutes required when working together \n" ); document.write( "let the completed job = 1, (a full tank) \n" ); document.write( "each pump does a fraction of the job. The two fractions add up to 1 \n" ); document.write( " \n" ); document.write( "multiply by 10 to clear the denominators, resulting in: \n" ); document.write( "2m + m = 10 \n" ); document.write( "3m = 10 \n" ); document.write( "m = 10/3 \n" ); document.write( "m = 3 \n" ); document.write( ": \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( "b/ \n" ); document.write( "in making one revolution a car wheel travels 200cm. \n" ); document.write( " how fast are the wheels spinning in revolutions per minute, \n" ); document.write( " when the car is traveling at 60km/h? \n" ); document.write( ": \n" ); document.write( "Let r = number of revs at 60 km/hr (convert 60 km/h to cm/min \n" ); document.write( "r = \n" ); document.write( "r = 500 rev per minute \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "c/ \n" ); document.write( "a girl paddles her kayak upstream from her home to her friends home \n" ); document.write( " taking 2.5 hours for the journey. returns that afternoon in 1.5 hrs \n" ); document.write( "if the current is flowing at 2.5 km/h \n" ); document.write( "find: \n" ); document.write( ": \n" ); document.write( "1/ her paddling speed in still water \n" ); document.write( "let s = speed in still water \n" ); document.write( "then \n" ); document.write( "(s-2.5) = effective speed upstream \n" ); document.write( "and \n" ); document.write( "(s+2.5) = effective speed downstream \n" ); document.write( ": \n" ); document.write( "Write a distance equation; dist = time * speed \n" ); document.write( "Up dist = down dist \n" ); document.write( "2.5(s-2.5) = 1.5(s+2.5) \n" ); document.write( "2.5s - 6.25 = 1.5s + 3.75 \n" ); document.write( "2.5s - 1.5s = 3.75 + 6.25 \n" ); document.write( "1s = 10 km/hr in still water \n" ); document.write( ": \n" ); document.write( "2/ the distance to the friends place. \n" ); document.write( "Find the dist upstream \n" ); document.write( "2.5(10-2.5) = \n" ); document.write( "2.5(7.5) = 18.75 km \n" ); document.write( "check using downstream equation \n" ); document.write( "1.5(10+2.5) = 18.75 km also, confirms our solution \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Hopefully, we can dry those tears! \n" ); document.write( " |