document.write( "Question 731585: Two cyclists 65 miles apart start biking toward each other at the same time. One cyclist bikes 5 miles per hour faster than the other; assume they travel at constant speeds. If they meet 2 hours later, how fast is the faster cyclist traveling? \n" ); document.write( "

Algebra.Com's Answer #447192 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
You can think of this as one cyclist standing still and
\n" ); document.write( "the other one approaching at the sum of their speeds
\n" ); document.write( "Let $\"+s+\"$ = the speed of the slower cyclist in mi/hr
\n" ); document.write( " $\"+s+%2B+5+\"$ = the speed of the faster cyclist in mi/hr
\n" ); document.write( "--------------------
\n" ); document.write( " $\"+65+=+%28+s+%2B+s+%2B+5+%29%2A2+\"$
\n" ); document.write( " $\"+65+=+%28+2s+%2B+5+%29%2A2+\"$
\n" ); document.write( " $\"+65+=+4s+%2B+10+\"$
\n" ); document.write( " $\"+4s+=+55+\"$
\n" ); document.write( " $\"+s+=+13.75+\"$
\n" ); document.write( " $\"+s+%2B+5+=+18.75+\"$
\n" ); document.write( "The faster cyclist's speed is 18.75 mi/hr
\n" ); document.write( "--------------
\n" ); document.write( "check:
\n" ); document.write( "Faster cyclist:
\n" ); document.write( " $\"+d%5B1%5D+=+18.75%2A2+\"$
\n" ); document.write( " $\"+d%5B1%5D+=+37.5+\"$
\n" ); document.write( "Slower cyclist:
\n" ); document.write( " $\"+d%5B2%5D+=+s%2A2+\"$
\n" ); document.write( " $\"+d%5B2%5D+=+13.75%2A2+\"$
\n" ); document.write( " $\"+d%5B2%5D+=+27.5+\"$
\n" ); document.write( "--------------
\n" ); document.write( " $\"+d%5B1%5D+%2B+d%5B2%5D+=+37.5+%2B+27.5+\"$
\n" ); document.write( " $\"+d%5B1%5D+%2B+d%5B2%5D+=+65+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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