document.write( "Question 731580: If a $25 investment is worth $50 today, how long must that $25 have been invested at 6% interest compounded twice a year? \n" ); document.write( "
Algebra.Com's Answer #447181 by stanbon(75887)\"\" \"About 
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If a $25 investment is worth $50 today, how long must that $25 have been invested at 6% interest compounded twice a year?
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\n" ); document.write( "50 = 25(1+(0.06/2))^(2t)
\n" ); document.write( "2 = (1.03)^2t
\n" ); document.write( "2t = log(2)/log(1.03)
\n" ); document.write( "2t = 23.45
\n" ); document.write( "t = 11.72 years
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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