document.write( "Question 731508:
\n" ); document.write( "A car leaves at 9 A.M. from a city and drives 45 miles per hour. At 11 A.M. a truck leaves from the city and drives at a rate of 60 miles per hour. At what time will the truck catch up to the car?
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Algebra.Com's Answer #447164 by checkley79(3341)\"\" \"About 
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D=RT
\n" ); document.write( "D=45T
\n" ); document.write( "D=60(T-2)
\n" ); document.write( "45T=60(T-2)
\n" ); document.write( "45T=60T-120
\n" ); document.write( "45T-60T=-120
\n" ); document.write( "-15T=120
\n" ); document.write( "T=-120/-15
\n" ); document.write( "T=8 HOURS AFTER THE CAR LEAVES THEY WILL MEET.
\n" ); document.write( "9 AM+8 HOURS=(17-12)=5 PM. ANSWER WHEN THEY MEET.
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