document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=731399>Question 731399</A>: <I><SPAN STYLE=\"word-break: break-all;\"> p^2-6p+c=0\r<BR>\n" );
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document.write( "find the value of c so that the equation will have exactly one rational solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #447107 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=447107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Need trinomial on the left side to be a perfect square.\r<BR>\n" );
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document.write( "Look at the p term:  -6p, if cut in half would be -3p.  We would expect in the squaring process that we had -3p + -3p, suggesting  constant term of -3 in the binomial.  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28p-3%29%28p-3%29=p%5E2-6p%2B9 ALIGN=MIDDLE  ALT=\"%28p-3%29%28p-3%29=p%5E2-6p%2B9\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=9 ALIGN=MIDDLE  ALT=\"c=9\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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